When a person inhales, air moves down the bronchus (windpipe) at 15 cm/s. The average flow...

Free

70.2K

Verified Solution

Question

Physics

When a person inhales, air moves down the bronchus (windpipe) at15 cm/s. The average flow speed of the air doubles through aconstriction in the bronchus. Assuming incompressible flow,determine the pressure drop in the constriction.

Answer & Explanation Solved by verified expert
4.1 Ratings (798 Votes)

Initial speed v = 15 cm / s = 0.15 m / s

speed after v ' = 30 cm / s = 0.30 m / s

Pressure drop = ( 1/ 2) ρ[ v ' ^ 2- v ^ 2]

                      = 0.5 * 1.225 * [ 0.0675 ]

                     = 0.043 Pa

(or)

By Bernoullis principle:

     Δp   = (1/2)density (v22 - v12 )   

             = (1/2)density (2v12 - v12 )  

              = (3/2)density ( v12 )

so:   Δp   = (3/2) * 1.29kg/m3 * (0.17 2 )

              = 0.0559 Pa

                      = 33.75 Pa


Get Answers to Unlimited Questions

Join us to gain access to millions of questions and expert answers. Enjoy exclusive benefits tailored just for you!

Membership Benefits:
  • Unlimited Question Access with detailed Answers
  • Zin AI - 3 Million Words
  • 10 Dall-E 3 Images
  • 20 Plot Generations
  • Conversation with Dialogue Memory
  • No Ads, Ever!
  • Access to Our Best AI Platform: Flex AI - Your personal assistant for all your inquiries!
Become a Member

Other questions asked by students