When a 7.00-g sample of RbBr is dissolved in water in a calorimeter that has a...

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When a 7.00-g sample of RbBr isdissolved in water in a calorimeter that has a total heat capacityof 3.090 kJÂ·Kâ€“1, the temperature decreases by 0.300 K. Calculatethe molar heat of solution of RbBr.

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3.7 Ratings (474 Votes)

Heat absorbed by calorimeter = (heat capacity of calorimeter)(Tf - Ti)

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = (3.090 kJ / K)*(0.300 K)

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 0.927 KJ

molar mass of RbBr = 165.37 g/mole.

moles RbBr = 7.00 g / 165.37 g

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 0.0423 moles.

= 0.927 kJ heat / 0.0423 moles RbBr = +21.9 kJ / mole of RbBr

molar heat of solution of RbBr = +21.9 KJ

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