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When 50.0 mL of 0.400 M Ca(NO3)2 is added to 50.0 mL of 0.800 M NaF,...

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Chemistry

When 50.0 mL of 0.400 M Ca(NO3)2 is added to 50.0 mL of 0.800 MNaF, CaF2 precipitates, as shown in the net ionic equation below.The initial temperature of both solutions is 30.00°C. Assuming thatthe reaction goes to completion, and that the resulting solutionhas a mass of 100.00 g and a specific heat of 4.18 J/(g ∙ °C),calculate the final temperature of the solution.

           Ca2+(aq) + 2 F-(aq) →CaF2(s)   ΔH° = -11.5 kJ

30.55°C

If there is additional information about the heat capacity ofthe calorimeter (58.3 J/°C) in the above questions, how would youapproach your answer?

Answer & Explanation Solved by verified expert
4.2 Ratings (678 Votes)
Given reaction is Initial temperature 30 degree CelsiusMoles of Calcium ions available Moles of CalciumnitrateMolarity x Volume50mL x 04M 20mmolMoles of    See Answer
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