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When 50.0 mL of 0.400 M Ca(NO3)2 is added to 50.0 mL of 0.800 M NaF,...

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Chemistry

When 50.0 mL of 0.400 M Ca(NO3)2 is added to 50.0 mL of 0.800 MNaF, CaF2 precipitates, as
shown in the net ionic equation below. The initial temperature ofboth solutions is 25.00°C. Assuming
that the reaction goes to completion, and that the resultingsolution has a mass of 100.00 g and a heat
capacity the same as water, calculate the final temperature of thesolution.
Ca2+(aq) + 2 F-(aq) → CaF2(s)
ΔH° = –11.5 kJ

When trying to solve this I get an answer of 26.1 degrees C.

I am basically doing T2 = 11500(.02)/(100x2.09) - 25 = 26.1.However I know this to be the wrong answer. Can someone help me seemy error?

Answer & Explanation Solved by verified expert
4.4 Ratings (796 Votes)
Answer We are given 500 mL of 0400 M CaNO32 is added to 500 mL of 0800 M NaF ti 250oC mass 100 g Ca2aq 2 Faq CaF2s H 115 kJ First we    See Answer
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