When 50.0 mL of 0.400 M Ca(NO3)2 is added to 50.0 mL of 0.800 MNaF, CaF2 precipitates, as
shown in the net ionic equation below. The initial temperature ofboth solutions is 25.00°C. Assuming
that the reaction goes to completion, and that the resultingsolution has a mass of 100.00 g and a heat
capacity the same as water, calculate the final temperature of thesolution.
Ca2+(aq) + 2 F-(aq) → CaF2(s)
ΔH° = –11.5 kJ
When trying to solve this I get an answer of 26.1 degrees C.
I am basically doing T2 = 11500(.02)/(100x2.09) - 25 = 26.1.However I know this to be the wrong answer. Can someone help me seemy error?
