When 4.00 moles of PCl5 (g) is put in a 1.00 L vessel the equilibrium: PCl3...

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When 4.00 moles of PCl5 (g) is put in a 1.00 L vessel theequilibrium: PCl3 (g) + Cl2 (g) <--> PCl5 (g) is established.At equilibrium [Cl2]e = 5.20 x 10^-3 M. What is Kc for thisequilibrium as written?
a.) 9.61 x 10^2
b.) 6.77 x 10^-6
c.) 1.48 x 10^5
d.) 9.0 x 10^-6
e.) impossible to determine

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3.7 Ratings (298 Votes)

Â Â Â Â Â Â Â Â Â Â Â Â PCl3 (g) + Cl2 (g) <--> PCl5

IÂ Â Â Â Â Â Â Â Â Â Â 0 Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 0 Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 4

CÂ Â Â Â Â Â Â Â Â 0.005Â Â Â Â Â Â Â Â Â Â 0.005Â Â Â Â Â Â Â Â Â Â Â Â -0.005

EÂ Â Â Â Â Â Â 0.005Â Â Â Â Â Â Â Â Â Â Â Â 0.005Â Â Â Â Â Â Â Â Â Â Â 3.995

Kc = [PCl5]/[PCl3][Cl2]

Â Â Â Â Â Â Â = 3.995/0.005*0.005

Â Â Â Â Â Â Â = 1.59*10⁵

c.) 1.48 x 10^5 >>>>> answer

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When 4.00 moles of PCl5 (g) is put in a 1.00 L vessel the equilibrium: PCl3...

Free

70.2K

Verified Solution

Question

Chemistry

When 4.00 moles of PCl5 (g) is put in a 1.00 L vessel theequilibrium: PCl3 (g) + Cl2 (g) <--> PCl5 (g) is established.At equilibrium [Cl2]e = 5.20 x 10^-3 M. What is Kc for thisequilibrium as written?
a.) 9.61 x 10^2
b.) 6.77 x 10^-6
c.) 1.48 x 10^5
d.) 9.0 x 10^-6
e.) impossible to determine

Answer & Explanation Solved by verified expert

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When 4.00 moles of PCl5 (g) is put in a 1.00 L vessel the equilibrium: PCl3...

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70.2K

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Chemistry

When 4.00 moles of PCl5 (g) is put in a 1.00 L vessel theequilibrium: PCl3 (g) + Cl2 (g) <--> PCl5 (g) is established.At equilibrium [Cl2]e = 5.20 x 10^-3 M. What is Kc for thisequilibrium as written?a.) 9.61 x 10^2b.) 6.77 x 10^-6c.) 1.48 x 10^5d.) 9.0 x 10^-6e.) impossible to determine

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When 4.00 moles of PCl5 (g) is put in a 1.00 L vessel theequilibrium: PCl3 (g) + Cl2 (g) <--> PCl5 (g) is established.At equilibrium [Cl2]e = 5.20 x 10^-3 M. What is Kc for thisequilibrium as written?
a.) 9.61 x 10^2
b.) 6.77 x 10^-6
c.) 1.48 x 10^5
d.) 9.0 x 10^-6
e.) impossible to determine