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What volume of 0.115 M HClO4 solution is needed to neutralize 41.00mL of 9.00

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What volume of 0.115 M HClO4 solution is needed to neutralize41.00mL of 9.00

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3.9 Ratings (399 Votes)

NaOH + HClO4 = NaClO4 + H2O

1 moleÂ Â 1mole

Acid Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Base

M₁ Â Â =Â Â Â 0.115M Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â M₂ =0.09M

V_1Â Â =Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â V₂Â Â =41ml

n₁Â Â = 1 Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â n₁ Â Â Â =1

M1V1Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â M2V2

Â Â n_{1Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â} Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â n₁

0.115*V1/1Â Â Â Â Â Â Â =Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 0.09*41/1

v1Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 32ml

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