volume occupied by butane = nRT/P
           Â
= 0.057*0.0821*298/1
           Â
= 1.4 L
no of mol of propane must be taken (n) =
PV/RT
         Â
= 1*1.4/(0.0821*298)
         Â
= 0.057 mol
mass of propane = n*mwt =
0.057*44Â Â
                Â
= 2.508 g
                    Â
Pentane     Hexane
Molar Mass (g/mol)Â Â Â Â Â
72.15Â Â Â Â Â 86.18
Mass
(g)Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â
0.541Â Â Â Â Â 0.646
volume of Pentane at STP = nRT/P
  n = w/mwt
  = (w/mwt)RT/P  (STP : P= 1 atm ,
T = 273k)
  = (0.541/72.15)*0.0821*273/1
  = 0.168 L
volume of hexane at STP = nRT/P
  n = w/mwt
  = (w/mwt)RT/P  (STP : P= 1 atm ,
T = 273k)
  = (0.646/86.18)*0.0821*273/1
  = 0.168 L
both the gases occupies same volume at STP
