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Chemistry

What is the ph of 0.10 MCa(C3H5O3)2?

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4.1 Ratings (687 Votes)

it is lactic acid salt : lactic acid Ka = 1.4 x 10–4

C3H5O3-   + H2O ------------------> C3H5O3H + OH-

0.10                                                  0                   0

0.10-x                                                x                  x

Ka = x^2 / 0.10-x

1.0 x 10^-14 / 1.4 x 10^-4 = x^2 / 0.10-x

7.14 x 10^-11 = x^2 / 0.10-x

x^2 + 7.14 x 10^-11 x - 7.14 x 10^-12 = 0

x = 2.67 x 10^-6

[OH-] = x = 2.67 x 10^-6 M

pOH = -log [OH-]

pOH = - log (2.67 x 10^-6)

pOH = 5.57

pH + pOH = 14

pH = 8.43


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