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What is the [OH-] of a solution which is 0.18 M in ammonium ion and 0.10...

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Chemistry

What is the [OH-] of a solution which is 0.18 M in ammonium ionand 0.10 M in ammonia?

The answer should be 1.0 x 10^-3. Please show al the work.Thanks!

Answer & Explanation Solved by verified expert
4.2 Ratings (490 Votes)

Let α be the dissociation of the weak base,NH4OH
                        NH4OH <---> NH4+ + OH-

initial conc.            c               0         0

change               -cα            +cα      +cα

Equb. conc.         c(1-α)        cα      cα

Dissociation constant, Kb = (cα x cα) / ( c(1-α)               

                                          = c α2 / (1-α)

In the case of weak bases α is very small so 1-α is taken as 1

So Kb = cα2

==> α = √ ( Kb / c )

Given Kb = 1.8x10-5

[NH4OH] = 0.10 M & [NH4+] = 0.18 M

      c(1-α) = 0.10 M     &   cα = 0.18 M

So [OH-] = cα = 0.18 M
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