Number of moles of H2SO4 = Molarity x volume in L
                                                     Â
= 0.253 M x (22.30/1000)L
                                                     Â
= 0.00564 mol
The chemical reaction between H2SO4 and NaOH is as follows:
                       Â
   H2SO4 +
2NaOHÂ Â Na2SO4 + 2H2O
1 mole of H2SO4 reacts with 2 moles of
NaOH
0.00564 mol of H2SO4 reacts with M moles
of NaOH
Mole of NaOH = ( 0.00564x2) / 1
  = 0.0113 mole of NaOH
So Molarity of NaOH , M = Number of moles / volume in L
                                   Â
= 0.0113mol / (0.025 L
                                   Â
= 0.452 M
