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What is the mass (in grams) of 9.06 * 1024 molecules of methanol (CH3OH)?

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Chemistry

What is the mass (in grams) of 9.06 * 1024 moleculesof methanol (CH3OH)?

Answer & Explanation Solved by verified expert
3.9 Ratings (567 Votes)

Molar mass of methanol , CH3OH=CH4O = At.mass of C + ( 4xAt.mass of H ) + At.mass of O

                                                             = 12 + ( 4x1) + 16

                                                             = 32 g/mol

We know that 1 mole of any compound contains avagadro number ( 6.023x1023) molecules

So 1 mole = 32 g of methanol contains 6.023x1023 molecules

M g of methanol contains 9.06x1024 molecules

M = ( 32x9.06x1024 )/ (6.023x1023 )

   = 481.3 g

Therefore the mass of methanol is 481.3 g
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