What is the concentration in % (v/v) of a methanol solution prepared by mixing 35.0 mL...

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Answer â€“ We are given volume of methanol = 35.0 mL , volume of water = 700 mL .

We need to calculate the concentration in % (v/v) of a methanol solution

First we need to calculate the volume of solution

We know ,

Volume of solution = volume of solute + volume of solvent

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 35.0 mL + 700 mL

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 735 mL

We know

concentration in % (v/v) of a methanol = volume of methanol / total volume of solution * 100 %

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 35.0 mL / 735 mL *100 %

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 4.76 %

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