What change in pH should be observed if 10.0 mL of 0.100 M NaOH is added...

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What change in pH should be observed if 10.0 mL of 0.100 M NaOHis added to 100 mL of a buffer that is 0.100 M inCH3COOH and 0.100 M in NaCH3CO2?Ka for acetic acid is 1.8 x 10-5.

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CH3COOH +H2O ----->CH3COO- + H3O+

0.1              0                0.1            0    initial

0.1-x                             0.1+x       +x    equlibirium

Ka= [CH3COO-][H3O+]/[CH3COOH]

1.8x10^-5= [0.1+x ][x] /[0.1-x] x=too small so ignored

x= 1.8x10^-5 x0.1 / 0.1

pH= -log 1.8x10^-5= 5-0.255 = 4.745

after adding NaOH

OH- + CH3COOH --->H2O + CH3COO-

0.001mol   0.01mol                0.01mol initial

0                 0.01-.001         0.01+0.001 at eq

Ka= [CH3COO-][H] /[CH3COOH]

1.8x10^-5 = [x][ 0.011] /[0.009] =1.222x

x=1.8x10^-5/ 1.222=1.47x10^-5

pH=-log 1.47x10^-5=5-0.167=4.883

change in pH =4.883- 4.745 = 0.088


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