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  3. we found p z 0 53 0 7019 and p z 1 21 0 8869...

We found P z 0 53 0 7019 and P z 1 21 0 8869...

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We found P z 0 53 0 7019 and P z 1 21 0 8869 Subtract the smaller area from the larger area to find the requested probability P 0 53 sz 1 21 P 0 53 z 1 21 P z 1 21 P z 0 53 0 8869

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