We do so by evaluating the function f h 2 h 4 16 for various...
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Calculus
We do so by evaluating the function f h 2 h 4 16 for various values of h close to the left side and the right side of h 0 Intuitively we do this because then we should be able to h find a value of f h as close to the limit as we like if we choose h sufficiently close to 0 Complete the tables for f h evaluated at the given values correct to six decimal places h 0 5 0 1 0 01 0 001 lim 2 h 4 16 h 0 h 0 0001 f h 34 481000 32 240801 h 0 5 0 1 0 01 0 001 0 0001 f h 21 875000 31 760799
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