We can now use the substitution u sin 8 so du 8 sec 4 u...
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Calculus
We can now use the substitution u sin 8 so du 8 sec 4 u Step 4 sec sin 8 Jn 3 15 4 We have determined that if we let u sin 8 then du cos 8 de on the interval 4 cos 8 de sin 0 du 15 4 5 2 Step 5 We can now evaluate the integral 15 4 5 2 1 15 4 U 2 cos 8 15 4 24 cos 8 du de Once more we must also make a substitution for the limits of integration When 8 TT 15 VS VTS Applying the substitution gives us the following result
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