Â
(C6H5)2
C2H2Br2Â Â
+Â Â Â KOHÂ Â Â
---------------->Â Â Â
(C6H5)2 C2
general          Â
340g                                                             Â
178.22g
Given
           Â
0.75g                   Â
0.75g                                Â
0
Here triethylene glycol is a solvent and KOH is excess
reagent
340g 1,2-dibromo-1,2-diphenylethane can from 178.22g diphenyl
acetylene.
0.75g 1,2-dibromo-1,2-diphenylethane can from
178.22*0.75/340=0.3931g diphenyl acetylene.