We are using 0.75 g of 1,2-dibromo-1,2-diphenylethane adn reacting with 0.75g KOH and 5 mL triethylene...

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We are using 0.75 g of 1,2-dibromo-1,2-diphenylethane adnreacting with 0.75g KOH and 5 mL triethylene glycol to producediphenyl acetylene.
What is the theoretical yield?

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4.1 Ratings (633 Votes)

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â (C₆H₅)₂ C₂H₂Br_2Â Â +Â Â Â KOHÂ Â Â ---------------->Â Â Â (C₆H₅)₂ C₂

generalÂ Â Â Â Â Â Â Â Â Â Â 340gÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 178.22g

Given Â Â Â Â Â Â Â Â Â Â Â Â 0.75gÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 0.75gÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 0

Here triethylene glycol is a solvent and KOH is excess reagent

340g 1,2-dibromo-1,2-diphenylethane can from 178.22g diphenyl acetylene.

0.75g 1,2-dibromo-1,2-diphenylethane can from 178.22*0.75/340=0.3931g diphenyl acetylene.

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