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  3. using y(t) = 110ekt, and the fact that y(30)= 75,

Using y(t) = 110ekt, and the fact that y(30)= 75, we can solve for k.y(t)...

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Using y(t) = 110ekt, and the fact that y(30)= 75, we can solve for k.y(t) = 110ekty(30) =110ek.=110ekThus, we have the following equation.k =

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