Using MATLAB: The velocity, v, and the distance, d, as a function of time, of a car...

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Mechanical Engineering

Using MATLAB:
The velocity, v, and the distance, d, as a function of time, ofa car that accelerates from rest at constant acceleration, a, aregiven by
= a n d = 12
Determine v and d at every second for the first 10 seconds for acar with acceleration of = 15 ft/s2. Your output must have exactlythe same format as the template table below. Note that dots havebeen added to the table below; you can count the dots to determinethe exact spacings. Also note the units.
Â·Â·Â·Â·Â·Â·Â·Â·Â·Â·Time (s) Â·Â·Â·Â·Â·Â·Â· Â·Â·Â·Distance (ft) Â·Â·Â·Â·Â·Â·Â·Â·Â·Velocity(mph)Â·Â·Â·Â·Â·Â·Â·Â·Â·Â·x.xÂ·Â·Â·Â·Â·Â·Â·Â·Â·Â·Â·Â·Â·Â·Â·Â·Â·x.xxe+yyÂ·Â·Â·Â·Â·Â·Â·Â·Â·Â·Â·Â·Â·Â·Â·x.xxx

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3.7 Ratings (299 Votes)

MATLAB CODE

clear
clc;
a = 15; %ft/s2 (acceleration)
for i = 1:10
Â Â Â t(i) = i; %time span
Â Â Â d(i) = 12 + (1/2)*a*t(i)^2; % initial distane is 12 ft.
Â Â Â v(i) = a*t(i)*(3600/5280); % 1 mile = 5280 ft and 1h =3600 sec
end
table = [t' d' v']

Ans

Time(s)	Distance(ft)	velocity (mph)
1.0000Â Â Â Â Â	19.5000	10.2273
2.0000Â Â Â	42.0000	20.4545
3.0000Â Â Â Â Â	79.5000	30.6818
4.0000Â Â Â Â	132.0000	40.9091
5.0000Â Â Â	199.5000	51.1364
6.0000Â Â Â	282.0000	61.3636
7.0000Â Â Â Â	379.5000	71.5909
8.0000Â Â Â Â	492.0000	81.8182
9.0000Â Â Â Â	619.5000	92.0455
10.0000Â Â Â	762.0000	102.2727

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