Use the HendersonHasselbalch equation to calculate the pH ofeach solut...

A no of moles of HF WGMWt 16520 0825moles molarity of HF no of moles volume in L 08 ....

Use the Hendersonâ€“Hasselbalch equation to calculate the pH of each solution: Part A a solution that is 16.5...

3.9 Ratings (573 Votes)

A. no of moles of HF = W/G.M.Wt

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 16.5/20Â Â = 0.825moles

molarity of HFÂ Â Â Â Â Â Â Â Â Â Â = no of moles /volume in L

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 0.825/0.125Â Â = 6.6 M

no of moles of NaFÂ Â Â = 22/42 = 0.524moles

molarity of NaFÂ Â Â Â Â Â Â Â Â = 0.524/0.125 = 4.192

Â Â Â Â Â Â Â Â Â PHÂ Â Â Â Â Â Â Â Â Â Â Â Â Â = Pka + log[NaF]/[HF]

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 3.17 + log4.192/6.6

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 3.17-0.1971 = 2.9729

part-B

Â Â Â Â no of moles of CH3NH2 = 1.23/31 = 0.03967 moles

Â Â Â Â no of moles of CH3NH3BrÂ Â = 1.3/112 = 0.0116moles

Â Â Â Â Â Â POH = Pkb + log[CH3NH3Br]/[CH3NH2]

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 3.3665 + log0.0116/0.03967

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 3.3665-0.534 = 2.8325

Â Â Â Â PHÂ Â = 14-POH

Â Â Â Â Â Â Â Â Â Â = 14-2.8325Â Â = 11.1675

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