Use the graph to find the limit L (if it exists). Ifthe limit does not exist, explain why. (If an answer does notexist, enter DNE.)
h(x) = -x/2 + x2
(a)
lim x→2 h(x)
L =
(Select One)
The limit does not exist at x = 2 because the functionis not continuous at any x value.
The limit does not exist at x = 2 because the functionapproaches different values from the left and right side of2.   Â
The limit does not exist at x = 2 because the functionvalue is undefined at x = 2.
The limit does not exist at x = 2 because the functiondoes not approach f(2) as x approaches 2.Thelimit exists at x = 2.
(b)
lim x→1 h(x)
L =
(Select One)
The limit does not exist at x = 1 because the functiondoes not approach f(1) as x approaches 1.
The limit does not exist at x = 1 because the functionapproaches different values from the left and right side of1.   Â
The limit does not exist at x = 1 because the functionis not continuous at any x value.
The limit does not exist at x = 1 because the functionvalue is undefined at x = 1.The limit exists at x= 1.