Use the following info for Questions 6-10. Classic Golf, Inc., manages five golf courses in Florida....

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Use the following info for Questions 6-10.

Classic Golf, Inc., manages five golf courses in Florida. Thedirector wishes to compare the rounds of golf played at the fivecourses, so he counted the rounds for a sample week. At the .05significance level, is there an actual difference in the numbers ofrounds playd at the five courses?

  • H0 : the #rounds played at the five courses is thesame
  • H1: the #rounds played at the five courses is notthe same

(Part of the data analysis is provided for you.)

Course     #Roundsplayed     (fe)    (fo -fe)    (fo -fe)2    (fo-fe)2/fe

Dogwood              124          104       20             400             3.846

Forsythia                74          104      -30             900             8.654

Starburst               104

Azalia                     98

Sunflower              120   

Golf Course Question #6: how was (fe)calculated?

A.

It's calculated from the #rounds played at Starburst.

B.

1040/10

C.

520/5

D.

20.8 x 5

QUESTION 7

  1. Golf Course Question #7: Calculate ?(fo - fe)2

    A.

    1590

    B.

    1592

    C.

    1594

    D.

    1596

QUESTION 8

  1. Golf Course Question #8: What is the criticalvalue of Chi-Square?

    A.

    9.263

    B.

    9.488

    C.

    11.070

    D.

    15.211

Golf Course Question #9: What is the computedvalue of Chi-Square?

A.

15.308

B.

16.517

C.

17.342

D.

18.166

QUESTION 10

  1. Golf Course Question #10: Whatis your decision?

    A.

    #Rounds played is the same at all 5

    B.

    #Rounds played is not the same at all 5

    C.

    Cannot be determined

Answer & Explanation Solved by verified expert
3.7 Ratings (609 Votes)

6)

total frequency=   520

expected frequncy,E = expected proportions*total frequency =520/5 = 104

answer: 520/5

7)

observed frequencey, fo expected proportion expected frequency,fe (fo-fe)^2 (fO-fE)²/fE
124 0.200 104.00 400.00 3.846
74 0.200 104.00 900.00 8.654
104 0.200 104.00 0.00 0.000
98 0.200 104.00 36.00 0.346
120 0.200 104.00 256.00 2.462

answer: ?(fo-fe)^2 = 1592

8)

level of significance, ?=   0.05              
Degree of freedom=k-1=   5   -   1   =   4
                  
  
Critical value =    9.488 [ Excel function: =chisq.inv.rt(?,df) ]          

9)

chi square test statistic,X² = ?(fo-fe)²/fe =   15.308

10)

since, test stat> criitcal value, reject Ho

answer: B.

#Rounds played is not the same at all 5


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