Use the distribution below to test that Plain M&Ms followthe stated distribution. Discuss your choice of ?. Would adifferent ? have changed your conclusion?
M&M states the following distribution for PlainM&Ms:
Red = 13%, Orange = 20%, Yellow = 13%, Green = 20%, Blue = 20%,Brown = 14%
Total number of plain M&M's: 665 Total number of red plainM&M's: 76 Total number of plain brown M&M's: 66 Totalnumber of blue plain M&M's: 179 Total number of orange plainM&M's: 140 Total number of green plain M&M's:119Â Â Total number of yellow plain M&M's: 85
Total number of peanut M&M's: 356 Total number of red peanutM&M's: 22 Total number of peanut brown M&M's: 34 Totalnumber of blue peanut M&M's: 55 Total number of orange peanutM&M's: 62 Total number of green peanut M&M's:72Â Â Total number of yellow peanut M&M's: 111
