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Use the density and molecular weight of limonene, linalool, and nonane to calculate the volumes of...

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Chemistry

Use the density and molecular weight of limonene, linalool, andnonane to calculate the volumes of the compounds you will need tomake the stock solution of 50 mM. Also calculatethe final concentration of those solutions after dilution.

Nonane: d = 0.718 g/mL, MW = 128.26, 99% pure

Limonene: d = 0.84 g/mL MW = 136.24, 96% pure

Linalool: d = 0.861 g/mL, MW = 154.25, 97% pure.

Preparing in 10mL volumetric flask.

Answer & Explanation Solved by verified expert
3.6 Ratings (289 Votes)
Ans 1 purity 99 Mass of 1 mL noname sample density x volume 0718 g mL x 1 mL 0718 g Thus actual amount of nonane in 0718 g sample 99 of 0718 g 071082 g So 1 ml of sample has 071082 g nonane Number of moles in 071082 g sample mass molecular mass 071082 g 12826 g mol1 0005542 moles Thus 1 mL of nonane has 0005542 moles Stock 50 mM solution 50 x 102 M 50 x 102 moles in 1 L 005 moles in 1000 mL Since 1000 mL contains 005 moles So 1 mL 005 1000 moles So 10 mL 005 1000 x 10 moles 00005 moles Thus 10 mL of 50 mM stock solution contains 00005 moles of the solute Preparation of final stock solution Since 0005542 mole is present in 1 mL So 1 mole 1 0005542 ml Or 00005 moles 1 0005542 x 00005 ml 00902197 mL Mass of    See Answer
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