USA Today reported that approximately 25% of all state prisoninmates released on parole become repeat offenders while on parole.Suppose the parole board is examining five prisoners up for parole.Let x = number of prisoners out of five on parole who become repeatoffenders.

x 0, 1, 2, 3, 4, 5

P(x) 0.212, 0.374, 0.224, 0.158, 0.031, 0.001

(a) Find the probability that one or more of the five paroleeswill be repeat offenders. (Round your answer to three decimalplaces.)

How does this number relate to the probability that none of theparolees will be repeat offenders?

These probabilities are not related to each other.

This is five times the probability of no repeat offenders.

This is the complement of the probability of no repeatoffenders.

These probabilities are the same.

This is twice the probability of no repeat offenders.

(b) Find the probability that two or more of the five paroleeswill be repeat offenders. (Round your answer to three decimalplaces.)

(c) Find the probability that four or more of the five paroleeswill be repeat offenders. (Round your answer to three decimalplaces.)

(d) Compute μ, the expected number of repeat offenders out offive. (Round your answer to three decimal places.) μ =prisoners

(e) Compute σ, the standard deviation of the number of repeatoffenders out of five. (Round your answer to two decimal places.) σ= prisoners