Under certain water? conditions, the free chlorine? (hypochlorous acid,? HOCl) in a swimming pool decomposes according to...

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Under certain water? conditions, the free chlorine?(hypochlorous acid,? HOCl) in a swimming pool decomposes accordingto the law of uninhibited decay. After shocking a? pool, the pool?boy, Geoff, tested the water and found the amount of free chlorineto be 2.4 parts per million? (ppm). ? Twenty-four hours? later,Geoff tested the water again and found the amount of free chlorineto be 2.1 ppm. What will be the reading after 2 days? (that is, 48?hours)? When the chlorine level reaches 1.0? ppm, Geoff must shockthe pool again. How long can Geoff go before he must shock thepool? again?

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From Uninhibted decay law expression for decomposition ofchlorine in swimming    See Answer
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