Two artillery bases are located at the points A and C represented in the figure....

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Two artillery bases are located at the points A and C represented in the figure. Each of the bases locates an enemy airplane at point B and measures the angles of elevation to the airplane. Given the elevation angles in the figure and the fact that the enemy airplane is 2,135 meters from the base at point C, how far apart, in meters, are the two bases? (Round your answer to the nearest tenth if necessary. Do not include any units.)

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To solve this problem we can use the Law of Sines in the triangle triangle ABC Given angle A 83circ angle C 77circ BC 2135 meters Steps 1 Calculate angle B angle B 180circ angle A angle    See Answer
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