Treatment of a 0.2496-g sample of impure potassium chloride with an excess of AgNO3 resulted in...

4.1 Ratings (852 Votes)

KClÂ Â +Â Â AgNO3 ---------------------->Â Â AgCl + KNO3

74.55g Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 143.3 g

??Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 0.2852 g

KCl needed = 74.55 x 0.2852 / 143.3

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 0.1484 g

% KClÂ Â = mass of KCl x 100 / sample mass

Â Â Â Â Â Â Â Â Â Â Â Â Â = 0.1484 x 100 / 0.2496

Â Â Â Â Â Â Â Â Â Â Â = 59.44 %

percentage of KCl in the sample = 59.44 %

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