To obtain information on the corrosion-resistance properties of a certain type of steel conduit, 45 specimens...

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To obtain information on the corrosion-resistance properties ofa certain type of steel conduit, 45 specimens are buried in soilfor a 2-year period. The maximum penetration (in mils) for eachspecimen is then measured, yielding a sample average penetration ofx = 52.4 and a sample standard deviation of s =4.5. The conduits were manufactured with the specification thattrue average penetration be at most 50 mils. They will be usedunless it can be demonstrated conclusively that the specificationhas not been met. What would you conclude? (Use ? =0.05.)
State the appropriate null and alternative hypotheses.

A- H0: ? ? 50
Ha: ? > 50

B-) H0: ? = 50
Ha: ? ? 50

C-) H0: ? = 50
Ha: ? > 50

D-) H0: ? > 50
Ha: ? = 50

Calculate the test statistic and determine the P-value.(Round your test statistic to two decimal places and yourP-value to four decimal places.)

z=
P-value=

State the conclusion in the problem context.

Reject the null hypothesis. There is not sufficient evidence toconclude that the true average penetration is more than 50mils.

Do not reject the null hypothesis. There is sufficient evidenceto conclude that the true average penetration is more than 50mils.    

Do not reject the null hypothesis. There is not sufficientevidence to conclude that the true average penetration is more than50 mils.

Reject the null hypothesis. There is sufficient evidence toconclude that the true average penetration is more than 50mils.

Answer & Explanation Solved by verified expert
3.9 Ratings (645 Votes)
Solution Given thatPopulation mean 50Sample mean 524Population standard deviation    See Answer
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