To convert from a given quantity of one reactant or product to the quantity of another...

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Chemistry

To convert from a given quantity of one reactant or product tothe quantity of another reactant or product:

First, convert the given quantity to moles. Use molar masses toconvert masses to moles, and use Avogadro's number (6.02×1023particles per mole) to convert number of particles to moles.

Next, convert moles of the given reactant or product to moles ofthe desired reactant or product using the coefficients of thebalanced chemical equation. For example, in the chemicalequation

2H2+O2→2H2O

the coefficients tell us that 2 mol of H2 reacts with 1 mol ofO2 to produce 2 mol of H2O.

Finally, convert moles of the desired reactant or product backto the desired units. Again, use molar masses to convert from molesto masses, and use Avogadro's number to convert from moles tonumber of particles.

part A. How many grams of NH3 can be produced from 3.19 mol ofN2 and excess H2.

part B. How many grams of H2 are needed to produce 14.94 g ofNH3?

part C. How many molecules (not moles) of NH3 are produced from3.33×10−4 g of H2?

2. When methane (CH4) burns, it reacts with oxygen gas toproduce carbon dioxide and water. The unbalanced equation for thisreaction is

CH4(g)+O2(g)→CO2(g)+H2O(g)

This type of reaction is referred to as a completecombustion reaction.

Part a. What mass of carbon dioxide is produced from thecomplete combustion of 2.00×10−3 g of methane?

Part b. What mass of water is produced from the completecombustion of 2.00×10−3 g of methane?

Part c. What mass of oxygen is needed for the completecombustion of 2.00×10−3 g of methane?

3. Aluminum reacts with chlorine gas to form aluminum chloridevia the following reaction:

2Al(s)+3Cl2(g)→2AlCl3(s)

Aluminum reacts with chlorine gas to form aluminum chloride viathe following reaction:

2Al(s)+3Cl2(g)→2AlCl3(s)

Part a. What is the maximum mass of aluminum chloride that canbe formed when reacting 31.0 g of aluminum with 36.0 g ofchlorine?

Express your answer to three significant figures and include theappropriate units.

4.

Determine the balanced chemical equation for this reaction.

C8H18(g)+O2(g)→CO2(g)+H2O(g)

Enter the coefficients for each compound in order, separated bycommas. For example, 1,2,3,4 would indicate one mole of C8H18, twomoles of O2, three moles of CO2, and four moles of H2O.

5. 1.66 g H2 is allowed to react with 10.3 g N2, producing 1.62g NH3.

Part A

What is the theoretical yield in grams for this reaction underthe given conditions?

Express your answer to three significant figures and include theappropriate units.

You are given 31.0 g of aluminum and 36.0 g of chlorine gas.

Part B

What is the percent yield for this reaction under the givenconditions?

Express your answer to three significant figures and include theappropriate units.

Answer & Explanation Solved by verified expert
3.9 Ratings (591 Votes)
Welcome to Aula Ya QA part A How many grams of NH3can be produced from 319 mol of N2and excess H2 part B How many grams of H2 are needed to produce 1494 g of NH3 part C How many molecules not moles of NH3 are produced from 333104 g of H2 MW of NH3 1x14 gmol 3x1gmol 17 gmol MW of N2 2 x 14 gmol 28 gmol MW of H2 2 x 1 gmol 2 gmol For part A we need the balanced equation of the reaction N2 3H2 2NH3 In the equation we can see that one mol of nitrogen produces 2 mol of ammonia If we have excess of hydrogen it means that all of the nitrogen reacts so we can establish a relation between the number of mol for nitrogen and the number of mol of product ammonia You can use the rule of three or conversion factors nNH3 319 mol x 21 638 mol To convert the mol into grams we multiply by the molecular weight MW gNH3 638 mol x 17 gmol 10846 g Part B In this question you see that the limiting reactant is going to be hydrogen because the total amount of ammonia produced from the 319 mol is much larger than 1494 g So we proceed like these First calculate the number of mol of ammonia nNH3 1494 g 17 gmol 088 mol When going back to the reaction we see that 3 mol of hydrogen produce 2 mol of ammonia    See Answer
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