A is flase because of PbCrO4 form pricipitate
B. Ksp = [Pb+2][CrO42-]
     1.8*10-14 =
[Pb+2][CrO42-]
[Pb+2][CrO42-] = 2.8*10-6 *6.6*10-5
                               Â
= 1.8*10-10
So will be pricipitate form PbCrO4 because of concentration
exeed the KsP .
B.A precipitate of PbCrO4 will form.
Ksp = [Pb+2][cl-]2
1.6*10-5 = [Pb+2][cl-]2
[Pb+2][cl-]2Â Â Â = 2.8*10-6
*(1.0)2
                Â
= 2.8*10-6
will not form PbCl2 pricipitate because of concentration not
exeed the Ksp
E.A precipitate of KCl will form. flase Kcl is soluble
C.Both a precipitate of PbCl2 and a precipitate of
PbCrO4 will form. Flase becuse of only pbcro4
pricipitate.
.
