Titration of a 15.0 mL solution of KOH requires 17.0 mL of 0.0250 M H2SO4 solution. What...

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Titration of a 15.0 mL solution of KOH requires 17.0 mL of0.0250 M H2SO4 solution.
What is the molarity of the KOH solution?
M=?

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The reaction between sulphuric acid and potassium hydroxide is an example of neutralisation reaction between a base and an acid to give salt and water. The reaction is:

H₂SO₄Â Â +Â Â Â KOH Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â K₂SO₄Â Â Â + H₂O

For any titration we know that:

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â M₁V₁ = M₂V_2,

Here, M₁ = molarity of KOH = ?, V₁ = volume of KOH = 15 mL,

Â Â Â Â Â Â Â Â Â M₂ = molarity of sulphuric acid = 0.0250, V₂ = volume of sulphuric acid = 17 mL.

by putting the values, we get the value of M₁ = 0.0283M.

Therefore, the molarity of KOH is 0.0283MÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â

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