this question, but calculate the 90% confidence intervalfor the coefficient for cable by hand (but use the SE fromthe software output) and do the test whether age andnumber of TVs should be dropped by hand (use ANVOA tableto get p-value and confirm with software).

The data in the table below contains observations onage, sex (male = 0, female = 1), number of television sets in thehousehold, cable (no = 0, yes = 1), and number of hours oftelevision watched per week. Using hours of television watched perweek as the response, you can use Minitab's Regress or R'slm() command [e.g., model <-lm(hours~age+sex+num.tv+cable)] to fit a least squares regressionmodel to all the other given variables.

Age:	22,22,50,43,54,24,15,23,34,18,58,19,26,15,21,30,37,44,29,27,30,17,15,21,47,26,13,39,22,20,14,47,21,38,23,32,19,15,21,18
Sex:	0,0,1,1,0,1,0,1,1,1,0,0,0,1,1,0,1,0,0,1,1,0,1,0,0,1,1,0,1,1,1,1,0,0,1,1,1,0,1,0
Num. TV:	2,2,1,1,1,1,2,1,1,1,2,1,1,1,1,2,2,2,1,1,2,1,2,1,1,1,2,2,1,1,1,1,1,1,2,1,2,1,1,2
Cable:	1,0,1,1,1,0,1,0,1,0,1,0,0,0,0,0,1,1,1,0,0,1,1,1,1,0,0,0,1,0,0,1,0,1,0,0,1,0,0,1
Hours TV:	28,16,18,20,25,14,21,7,12,14,15,12,10,11,12,18,17,20,21,15,17,18,13,21,23,11,10,21,13,12,10,19,12,21,8,16,13,9,11,21

What is the estimated value of the regression coefficient forage?  [2 pt(s)]

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What is the estimated value of the regression coefficient forcable?  [2 pt(s)]

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According to the regression equation, which of the followingstatements is true?
Females watch television 3.577 hours more per week thanmales.
Males watch television 3.577 hours more per week thanfemales.
From the data given, one can not tell which gender watches moretelevision per week.
Females watch television approximately the same number of hours perweek as males.
[2 pt(s)]

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What is the value of the test-statistic for the overallregression significance test?  [3 pt(s)]

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What are the degrees of freedom associated with thetest-statistic? Numerator:  Denominator:  [1pt(s)]

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Select the interval below that contains the p-value for thistest.
p-value ? 0.001
0.001 < p-value ? 0.01
0.01 < p-value ? 0.05
0.05 < p-value ? 0.1
0.1 < p-value ? 0.25
p-value > 0.25
[3 pt(s)]

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Compute a 90% confidence interval for the coefficient forcable. Lower Bound:  Upper Bound:  [3pt(s)]

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Compute a 95% confidence interval for the mean number of hourswatched by 18-year old females with cable and 2 TV sets. LowerBound:  Upper Bound: [3 pt(s)]

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Compute a 95% prediction interval for the mean number of hourswatched by 18-year old females with cable and 2 TV sets. LowerBound:  Upper Bound: [3 pt(s)]

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Test whether age and number of TV sets are needed in the modelor should be dropped. What is the value of thetest-statistic?  [3 pt(s)]

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What are the degrees of freedom associated with this test?Numerator:  Denominator:  [1 pt(s)]

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Select the interval below that contains the p-value for thistest.
p-value ? 0.001
0.001 < p-value ? 0.01
0.01 < p-value ? 0.05
0.05 < p-value ? 0.1
0.1 < p-value ? 0.25
p-value > 0.25
[3 pt(s)]

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