this is my matlab code for class, my professor commented \"why isthe eps an input when it is set inside the function and notspecified as a variable?

how do i fix?

function[] = ()

%Declare Global Variables

global KS;

global KC;

KC = 0;

KS = 0;

End = 0;

while (End == 0)

choice = questdlg('Choose a function', ...

'Fuction Menu', ...

'A','B','B');

switch choice;

case 'A'

Program = 'Start';

while strcmp(Program,'Start');

Choice = menu('Enter the Trigonometric Function you wish tocompute', 'Sin', 'Cos','End');

  

switch Choice;

case 1 %sine

x = input('Input an angle (in Radians):\n'); %x = theta

eps = input('Input a value for epsilon:\n'); %eps=tolerance

[sum] = sine(x,eps);

fprintf('Matlab answer: %5.2f\n',sin(x))

fprintf('Taylor answer: %5.2f\n',sum)

fprintf('KS = %d\n',KS)

fprintf('KC = %d\n',KC)

case 2 %cosine

x = input('Input an angle (in Radians):\n'); %x = theta

eps = input('Input a value for epsilon:\n'); %eps=tolerance

[sum] = cosine(x,eps);

fprintf('Matlab answer: %5.2f\n',cos(x))

fprintf('Taylor answer: %5.2f\n',sum)

fprintf('KS = %d\n',KS)

fprintf('KC = %d\n',KC)

case 3

Program = 'End';

end

end

case 'B'  

% Triangle 1 Given Values

A = 1.0472;

b = 7;

C = 0.5236;

%Finding sides a and c and angle B using Law of Sines

B = pi - (A+C);

c = sine (C) / (sine(B)/b);

a = sine (A) / (sine(B)/b);

  

disp(['Triangle 1'])

fprintf('angle B in radians = %f\n', B);

fprintf('length of side a = %f\n', a);

fprintf('length of side c = %f\n', c);

%Triangle 2 Given Values using Law of Sines and C osines

a = 3;

B = 1.5708;

c = 4;

%Finding side b and angles A and C

b = sqrt((a^2)+(c^2)-(2*a*c*cosine(B)));

C = asin(c * (sine(B)/b));

A = asin(a * (sine(B)/b));

disp(['Triangle 2'])

fprintf('angle of C (in radians) = %f2\n', C);

fprintf('length of side b = %f2\n', b);

fprintf('angle A (in radians) = %f2\n', A);

fprintf('KS = %d\n',KS)

fprintf('KC = %d\n',KC)

end

End = input('Enter 0 to continue or other # to stop: ');

end

%Sine function

function[sum]= sine (x,eps)

KS = KS + 1;

eps = 0.0001;

sum=0;

i=0;

k=1;

while abs(k)>eps

%Taylor Series of Sine

k = (((-1).^i)*((x).^(2*i +1)))/(factorial((2*i)+1));

i = i + 1;

sum= sum+k;

end

end

%Cosine function

function [sum] = cosine (x,eps)

KC =KC + 1;

eps=0.0001;

sum=0;

i=0;

k=1;

  

while abs(k)>eps

%Taylor Series of Cosine

k = (((-1).^i)*((x).^(2*i)))/(factorial((2*i)));

i = i + 1;

sum= sum+k;

end

end

end