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4.3 Ratings (572 Votes)

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 2HI_(g)Â Â Â Â Â Â â‡Œ Â Â H_2(g) + I_2(g)

IÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 0.16Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 0Â Â Â Â Â Â Â Â 0

CÂ Â Â Â Â Â Â Â Â Â Â Â Â -2*0.0227Â Â Â Â Â Â Â 0.0227 0.0227

EÂ Â Â Â Â Â Â Â Â Â Â 0.16-2*0.0227 0.0227Â Â 0.0227

Â Â Â Â Â Â Â Â Â Â Â Â Â 0.1146

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Kc = [H2][I2]/[HI]²

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 0.0227*0.0227/(0.114)²Â Â Â = 0.039

Kc>Qc the equilibrium shift ot right side.

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