There is an interesting story involving Blaise Pascal, Pierre Fermat, and the Chevalier de Mere. Consider...

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There is an interesting story involving Blaise Pascal, PierreFermat, and the Chevalier de Mere. Consider the events A = {atleast one ‘one’ would appear when four six- sided dice are rolled}and B = {a pair of ‘ones’ would appear at least once when twosix-sided dice are rolled 24 times}. In the 1600s, French gamblersbet on whether event A will occur. They also bet on whether event Bwill happen. Many thought that these two events were equallylikely. The Chevalier de Mere was one among probably many whothought these two games had an equal chance of success. Was heright? Compute Pr(A) and Pr(B) to justify your answer.

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No he was not right Explanation Probability of not getting one in one roll in dice is 56 Therefore probability of not getting one in four roll of a dice is 56 4 04823 Since the roll of dice is independent See Answer

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