The Vector Field f(x, y) = (2x + 2y^2)i + (4xy - 6y^2)j has exactly one...

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The Vector Field f(x, y) = (2x + 2y^2)i + (4xy - 6y^2)j hasexactly one potential function f (x, y) that satisfies f(0, 0).Find this potential function , then find the value of thispotential function at the point (1, 1).

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Step 1we haveNowAndStep 2we know that1we can writeequate fy 4xy hy with Q 4xy    See Answer
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