The value of the equilibrium constant for the electrochemical reaction MnO4–(aq) + 2H+(aq) + ½Cl2(g) ⇌Mn2+(aq)+ ClO3–(aq) +H2O(aq) is 5.88 x10–5. What...

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The value of the equilibrium constant for the electrochemicalreaction

MnO4–(aq) +2H+(aq) + ½Cl2(g)⇌Mn2+(aq)+ClO3–(aq)+H2O(aq)

is 5.88 x10–5. What is the value of the equilibriumconstant for the reverse reaction?

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1 answer Chemistry Best Answer First split up the reaction into halfreactions To do this simply use the elements that are oxidised or reduced but not the other In this case those elements are Mn and Cl so make a separate equation for each Ignore states for now you    See Answer
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