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  3. the value of kc for the reaction: n2o4(g) ↔

The value of Kc for the reaction: N2O4(g) ↔ 2NO2 (g) is 0.21 at 373K. If a...

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Chemistry

The value of Kc for the reaction:

N2O4(g) ↔ 2NO2 (g)

is 0.21 at 373K. If a reaction vessel at that temperatureinitially contains 0.030M NO2 and 0.030MN2O4, what are the concentrations of the twogases at equilibrium? First, the reaction quotient (Q) [page 645 oftextbook] must be calculated, and then use the I.C.E table [page648-650 of the textbook] to determine the equilibriumconcentrations.

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3.5 Ratings (316 Votes)

                                     N2O4(g) ↔ 2NO2 (g)

initial                           0.03              0.03

change                     -x                    +2x

at equlibrium            0.03-x           0.03+2x

                 Kc = [NO2]2 /[N2O4]

               0.21   = (0.03+2x)2/0.03-x

            0.0063-0.21x = (0.03)2 + 4x2 + 0.12

             4x2 + 0.33x-0.0054 =0

            x=0.0139

[N2O4] = 0.03-x

             = 0.03-0.0139 = 0.0161M

[NO2]    = 0.03+2x

             = 0.03+2*0.0139 = 0.0578M
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