The strength of the magnetic field within a solenoid is B = 3.9 x 10-2 T...

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The strength of the magnetic field within a solenoid is B = 3.9x 10-2 T (outside the solenoid B = 0). A smaller, single loop isplaced in the solenoid parallel to the plane of each loop in thesolenoid. The resistance of the solenoid is 5.4 Ω, the resistanceof the loop is 0.29 Ω, the diameter of the solenoid is 0.07 m, andthe diameter of the loop is 0.04 m. An emf of 12 V is placed acrossthe ends of the solenoid and the length of the solenoid is 0.4m.

1) What is the total number of turns of the solenoid? N =turns

2) What is the magnitude of the magnetic flux through the loopinside the solenoid (remember, it only has one turn and the normalto the loop is parallel to the axis of the solenoid.) flux =T-m2

3) If the emf across the solenoid is varied so that the currentin the solenoid now decreases to zero at a constant rate over atime interval of 7.8 seconds, what is the current through the loopduring this time? (If the direction of the induced current in theloop is in the same direction as the current in the solenoid, giveyour answer as a positive value; if the direction of the inducedcurrent in the loop is in the opposite direction compared to thecurrent in the solenoid, give your answer as a negative value.) I=

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