The So's Hobby Shop carries a line of radio-controlled model racing cars. Average daily demand for...

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Operations Management

The So's Hobby Shop carries a line of radio-controlled modelracing cars. Average daily demand for the model cars is 100 with astandard deviation of 30. Unit inventory holding cost is estimatedat $0.90/year. The shop purchases the model cars from one supplier.It is estimated that the ordering cost is $100 per order. Thedelivery lead time is 10 working days. Mr. So decides to use aReorder Point System to control the inventory of the model cars andwants to achieve a service level of 90%. Assume 300 working daysper year.

  1. (3 points) Determine the optimal reorder point R and orderquantity EOQ. (Hint: R = average demand during lead time + safetystock)
  1. (3 points) Using the R and Q determined in part a), what is theaverage inventory in the shop? (Hint: average inventory = EOQ/2 +safety stock)
  1. (4 points) Mr. So is considering a new supplier who can deliverthe same line of model cars with a perfectly reliable lead time ofonly 3 working days. Estimate the potential annual savings ininventory holding cost by switching to this new supplier. (Hint:the saving = holding cost * reduction of average inventory)

Answer & Explanation Solved by verified expert
4.4 Ratings (644 Votes)

a)

Daily Demand µD = 100
Standard Deviation of Daily Demand σD = 30
Working days per year n = 300
Annual Demand D = n*µD 30,000
Lead Time (Days) L = 10
Desired Service level α = 90%
Z-value corresponding to Service Level Zα = NORMSINV(α) 1.28
Safety stock ss = ZασD √L 121
Reorder Point R = µD*L + ss 1,121
Annual Holding Cost per Unit H = $0.90
Ordering Cost per Order S = $100
Optimal Order Qty Q* = √(2SD/H) 2,582

Optimal reorder point, R = 1121

EOQ = 2582

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b)

Average inventory = EOQ/2 + Safety stock

= 2582/2 + 121

= 1412

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c)

New lead time, L = 3 days

Revised safety stock = 1.28*30*sqrt(3)

= 67

EOQ remains unchanged.

New average inventory = 2582/2+67

= 1358

Reduction in average inventory = 1412 - 1358

= 54

Savings = 54*0.9

= $ 48.6


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