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The solutions at the two Pb electrodes of a concentration cell were prepared as follows: Cell A:...

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Chemistry

The solutions at the two Pb electrodes of a concentration cellwere prepared as follows:

Cell A: A mixture of 1.00 mL of 0.0500 MPb(NO3)2 with 4.00 mL of 0.0500 M KX (the soluble potassium salt ofan unspecified monovalent ion X-). Some PbX2(s) precipitates.

Cell B: 5.00 mL of 0.0500 M Pb(NO3)2.

The cell potential was measured to be 0.05100 V at 25 °C.

1.)By use of the Nernst equation, determine the concentration(M) of Pb2+ in the solution of Cell A.

2.)In Cell A, how many moles of X- have reacted with Pb2+?

3.)What is the concentration (M) of X- in the solution of cellA.

4.) Calculate Ksp of PbX2.

Answer & Explanation Solved by verified expert
4.5 Ratings (768 Votes)
A At Anode PbA s Pb2A 2e Eoxidation 013 V At Cathode Pb2B 2e PbB s Ered uction 013 V Ecell E redEox0 The Nernst Eqn to calculate Pb2A E 0 E Ecell 00591n logPb2APb2B 005100 0    See Answer
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