The solubility product for barium sulfate is 1.1*10^-10.Calculate the molar solubility of barium sulfate.
1) 5.5*10^-11 mol/L
2) 1.1 *10^-5 mol/L
3) 2.1*10^-5 mol/L
4) 1.1*10^-10 mol/L
5) 2.2*10^-10 mol/L
I don't understand how to solve this. I'm stuck. Can anyone helpme soon as possible as fast? Thank you.
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