The relationship between CO2 gas produced to sugar consumed is shown below. m = n / 2s where...

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Biology

The relationship between CO2 gas produced to sugarconsumed is shown below.

m = n / 2s

where m is the number of moles of sugar consumed,n is the number of moles of CO2 produced, ands is the number of simple sugars in that sugar.

This means that for:

a monosaccharide, 2 CO2 molecules are produced permolecule of sugar

a disaccharide, 4 CO2 molecules are produced permolecule of sugar

a trisaccharide, 6 CO2 molecules are produced permolecule of sugar

Calculating the Rate of Respiration

First, use the Ideal Gas Law to convert the volume of gas tomolecules. This is measured in moles, not the number of individualmolecules. The Ideal Gas Law relates the moles of CO2gas molecules to its volume as shown in the equation below.

PV = nRT

where P is the atmospheric pressure in the lab,V is the volume in liters, n is the number ofmoles of CO2, R is the gas constant 0.082L-atm/mole-Kelvin, and T is the temperature in Kelvin.

Next, convert the moles of CO2 molecules produced tothe moles of sugar consumed using the equation shown below.

m = n / 2s

Finally, combine several calculations to convert the results tomilligrams of sugar fermented per minute:

convert from moles to grams

convert from grams to milligrams

divide by the length of respiration

The formula is below.

f = 1000mw / t

where f is the mg of sugar fermented per minute,m is the number of moles of sugar consumed, w isthe molecular weight of the sugar in g/mole, and t is therespiration time in minutes.

For example, if 1 L of CO2 is collected when yeast isincubated with maltose for 5 minutes and the final temperature ofthe flask is 294.5 K, the milligrams of sugar fermented per minuteare calculated as follows:

moles of CO2 = (1 atm × 1 L CO2) ÷ (0.082L-atm/mole-Kelvin × 294.5 K)
moles of CO2 = 0.041 moles

moles of maltose consumed = 0.04141 moles ofCO2produced ÷ (2 × 2 simple sugars in maltose)
moles of maltose consumed = 0.01035 moles

mg of maltose per minute = (0.01035 moles maltose) × (MW ofmaltose) × (1000 mg/g) ÷ (5 minutes)  
mg of maltose per minute = 708.6 mg/min

SugarInformation Table
SugarSugar TypeMolecular weight
glucosemono180.2 g/mole
fructosemono180.2 g/mole
maltosedi342.3 g/mole
maltotriosetri504.4 g/mole

For each of the sugars fermented by yeast, fill in the chartbelow to determine the volume of CO2 production.

Results Table(my answers)

Sugar

Initial Gas
Volume at t = 0 minutes (mL)

Final Gas
Volume at t = 1 minutes (mL)

Volume of Co2 Produced
Final - Initial (mL)

glucose

0.0 ml

4.3 ml

4.3 ml

fructose

0.0 ml

1.3 ml

1.3 ml

maltose

0.0 ml

5.1 ml

5.1 ml

maltotriose

0.0 ml

1.0 ml

1.0 ml

For each of the sugars fermented by yeast, fill in the chartbelow to determine the mg of sugar consumed per minute duringfermentation.

Calculations Table

Sugar

MW (g/mole)

Moles of CO2 produced

Moles of Sugar consumed

mg of sugar/min

fructose

maltose

maltotriose

My answers

Glucose temp 299.0k after 1 minute and 4.3ml in syringe

fructose temp 296.0k after 1 minute 1.3ml of gas in thesyringe

maltose temp 300.0k after 1 minute 5.1 ml

maltotriose temp 295.6k after 1 minute 1.0 ml

Answer & Explanation Solved by verified expert
3.6 Ratings (677 Votes)
Rate of respirationThe measurement of respiration is very important because itprovides a window through which we can determine the    See Answer
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