The reaction CH 4 (g) 2 H 2 S(g) CS 2 (g) 4 H 2 (g) has an equilib...

construct the ICE table CH 4 g 2 H 2 Sg CS 2 g 4 H 2 g I 02 06 02 06 C x 2x ....

The reaction CH4(g) + 2 H2S(g) â†” CS2(g) + 4 H2(g) has an equilibrium constant of 2.73...

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Chemistry

The reaction CH₄(g) + 2 H₂S(g) â†”CS₂(g) + 4 H₂(g) has an equilibrium constantof 2.73 at a specific temperature. The initial concentrations ofthe reactants and products are [CH₄] = [CS₂]= 0.200 M and [H₂S] = [H₂] = 0.600 M. What isthe equilibrium concentration of the H₂ if, atequilibrium, [CH₄] = 0.150 M?

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construct the ICE table

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â CH₄(g)Â Â Â + 2 H₂S(g)Â Â Â Â Â â†” CS₂(g)Â Â Â +Â Â Â Â 4 H₂(g)

IÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 0.2Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 0.6Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 0.2Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 0.6

CÂ Â Â Â Â Â Â Â Â Â Â Â Â Â -xÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â -2xÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â +xÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â +4x

EÂ Â Â Â Â Â Â Â Â Â Â Â Â 0.2-xÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 0.6-2xÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â 0.2+xÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â 0.6+4x

he has given equilibrium concentration of CH4

= [CH4] = 0.15Â Â

but from ICE table equilibrium concentration of CH4 = 0.2-x

0.2-x = 0.15

x = 0.2 - 0.15 = 0.05M

now equilibrium concentratiof H2 from ICE table

[H2] = 0.6 + 4x

put the above obtained x value here

= 0.6 + 4 (0.05)

= 0.6 + 0.2

[H2] at equilibrium= 0.8M

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