The reaction below was performed with 0.342 grams of K2CO3 (molar mass = 138.21 g/mol). After...

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Chemistry

The reaction below was performed with 0.342 grams of K2CO3(molar mass = 138.21 g/mol). After the reaction was complete 0.0675grams of CO2 was recovered. What was the percent yield to 2significant figures?

K2CO3(s) --> K2O(s) + CO2(g)

The correct answer is 62 %, but I don't understand how they gotthere. Please help explain the steps

Answer & Explanation Solved by verified expert
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Following isthe complete Answer Explanation for the givenQuestion intypedformatAnswerPercent yield of the reaction 620 ie correct up to 2 significant figuresExplanationFollowing is the completeExplanation for the aboveAnswerGivenbalancedreactionK2CO3 sK2O s CO2 g Equation    See Answer
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