The position of a weight attached to a spring is s(t)= -3 cos 4xt inches...

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Algebra

The position of a weight attached to a spring is s(t)= -3 cos 4xt inches after t seconds. Complete parts a)-d) below.a) What is the maximum height that the weight rises above the equilibrium position?b) What are the frequency and period?The frequency of the oscillation is cycles per sec(Type an integer or a fraction. Type an exact answer, using a as needed.)The period of the oscillation is sec(Type an integer or a fraction. Type an exact answer, using x as needed.)c) When does the weight first reach its maximum height?after sec(Type an integer or a fraction Type an exact answer, using as needed.)d) Calculate and interpret s(1.3)s(1.3)= (Round to the nearest integer as needed.)Interpret s(1.3) Choose the correct answer below.OA After 1.3 sec, the weight is about 2 in above the equilibrium positionOB. After 1:3 sec, the weight is about in above the equilibrium positionOc. After 2 sec, the weight is about 1.3 in above the equilibrium position.27

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The position of a weight attached to a spring is s(t)= -3 cos 4xt inches after t seconds. Complete parts a)-d) below.a) What is the maximum height that the weight rises above the equilibrium position?b) What are the frequency and period?The frequency of the oscillation is cycles per sec(Type an integer or a fraction. Type an exact answer, using a as needed.)The period of the oscillation is sec(Type an integer or a fraction. Type an exact answer, using x as needed.)c) When does the weight first reach its maximum height?after sec(Type an integer or a fraction Type an exact answer, using as needed.)d) Calculate and interpret s(1.3)s(1.3)= (Round to the nearest integer as needed.)Interpret s(1.3) Choose the correct answer below.OA After 1.3 sec, the weight is about 2 in above the equilibrium positionOB. After 1:3 sec, the weight is about in above the equilibrium positionOc. After 2 sec, the weight is about 1.3 in above the equilibrium position.27