The pH of a 0.392 M solution of the conjugate base, A-, of a weak acid,...

3.6 Ratings (317 Votes)

pH = 11.60

[ A- ] = 0.392 M

[H+] = 10^-pH

Â Â Â Â Â Â Â Â Â = 10^-11.60

Â Â Â Â Â Â Â Â Â Â = 2.5 x 10^-12 M

[OH-] = 1.0 x 10^-14 / 2.5 x 10^-12 = 4 x 10^-3 M

A-Â Â + H2OÂ Â ---------------------> AH + OH-

0.392Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 0Â Â Â Â Â Â Â Â Â 0

0.392-xÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â xÂ Â Â Â Â Â Â Â Â Â x

x = [OH-] = 4 x 10^-3 M

Kb = x^2 / 0.392 -x

kb = (4 x 10^-3)^2 / (0.392 - 4 x 10^-3)

Kb = 4.12 x 10^-5

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