The null and alternate hypotheses are H 0 d 0 H 1 d 0 The fo...

The null and alternate hypotheses are: H0 : Î¼d â‰¤ 0 H1 : Î¼d > 0 The following...

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Question

Statistics

The null and alternate hypotheses are:
H₀ : Î¼_d â‰¤ 0
H₁ : Î¼_d > 0
The following sample information shows the number of defectiveunits produced on the day shift and the afternoon shift for asample of four days last month.
Day
1 2 3 4
Day shift 12 12 16 19
Afternoon shift 12 10 16 18
At the 0.100 significance level, can we conclude there are moredefects produced on the day shift? Hint: For thecalculations, assume the day shift as the first sample.
State the decision rule. (Round your answer to 2 decimalplaces.)
Compute the value of the test statistic. (Round youranswer to 3 decimal places.)
What is the p-value?
Between 0.10 and 0.15
Between 0.001 and 0.005
Between 0.005 and 0.01
What is your decision regarding H₀?
Do not reject H₀
Reject H₀

Answer & Explanation Solved by verified expert

4.1 Ratings (828 Votes)

a Decision ruleSample size n 4Degrees of freedom df n1 413Significance level 010Right tailed test For right tailed test Critical value tt010t010 for 3 degrees of freedom See Answer

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