The nuclide 236U decays with emission of an alpha particle with measured energy of 4.448 MeV...

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Physics

The nuclide 236U decays with emission of an alpha particle withmeasured energy of 4.448 MeV and an accompanying gamma photon withmeasured energy of 49 keV. What is the product nucleus and doesthis particular decay of 236U occur to the ground state or andexcited state of the product nuclide?

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a The general equation of an alpha decay from a parent nucleusP to a daughter nucleus D is given byHere P 236 USo A4 236A 2364 232For Uranium    See Answer
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